Ivan Kalvachev wrote:
> You know, multiply is usually faster than division, so if these sums
> are constant, you can probably calculate reciprocals and multiply in
> the loop.
> {sr0=1/s0;...; v0*=sr0};
Thanks. It definitely helps. :)
Updated 5.1-to-stereo benchmark:
liba52 1.756
ffac3 2.420
-Justin